Program to search a number using Linear Search

#include<iostream.h>
main()
{
int n, a[20],ser,i,flag=0;
count<<"Enter the size of an array:"; cin>>n;
count<<"Enter the elements to array:\n";
for(i=0; i<n; i++) cin>>a[i];
cout<<"\n Enter the elents to search:"; cin>>ser;
for(i=0; i<n; i++)
{
if(ser == a[i])
{
flag = 1;
break;
}
}
if(flag == 1)
cout<<"\n Element "<<ser<<"is found in the array\n";
else
cout<<"\n Element "<<ser<<"is not found in the array\n";
return (0);
}

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OUTPUT
Enter the size of an array: 5
Enter the elements to array:
1
4
6
9
7
Enter the element to search: 9
Element 9 is found in the array
-----
Enter the size of an array: 4
Enter the elements to array:
9
5
7
3
Enter the element to search: 4
Element 4 is not found in the array