C Program to find the reverse of a number

#include <stdio.h>

int main() {
int num, reversed = 0, remainder;

// Input from user
printf("Enter an integer: ");
scanf("%d", &num);

while (num != 0) {
remainder = num % 10; // Get the last digit
reversed = reversed * 10 + remainder; // Build the reversed number
num = num / 10; // Remove the last digit
}

printf("Reversed number: %d\n", reversed);
return 0;
}

 

Output:
Enter an integer: 1234
Reversed number: 4321

Explanation:

• The program uses a while loop to extract the last digit of the number using the modulus operator %.

• It then multiplies the reversed number by 10 and adds the last digit.

• The original number is divided by 10 to remove the last digit.

• This continues until the number becomes 0.